Question
Show that the function given by f (x) = sin x is increasing in $\left(0, \frac{\pi}{2}\right)$

Answer

The function is f (x) = sin x
Then, f’(x) = cos x
Since for each x $\in$ $\left(0, \frac{\pi}{2}\right)$, cos x > 0, we have f’(x) > 0
Therefore, f’ is strictly increasing in$\left(0, \frac{\pi}{2}\right)$.

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