Question
Show that $(x + 2)$ is a factor of $f(x) = x^3+4 x^2+x-6 $.

Answer

$ \text { Given: } f(x)=x^3+4 x^2+x-6 $
$ \text { Now, } f(-2)=(-2)^3+4(-2)^2+(-2)-6 $
$ =-8+16-2-6 $
$ =0$
$\therefore(\mathrm{x}+2) \text { is a factor of } \mathrm{f}(\mathrm{x})=\mathrm{x}^3+4 \mathrm{x}^2+\mathrm{x}-6 \text {. }$

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