Question
Show that $x = -2$ is a solution of $3x^2 + 13x + 14 = 0.$
✓
Answer
Given equation is $3x^2 + 13x + 14 = 0$
Substituting x = -2 in L.H.S. of above equation, we get
$L.H.S. = 3(-2)^2 + 13 \times (-2) + 14$
$= 12 - 26 + 14$
$= 26 - 26$
$= 0$
$= R.H.S.$
Hence, x = -2 is a solution of the given equation.
Substituting x = -2 in L.H.S. of above equation, we get
$L.H.S. = 3(-2)^2 + 13 \times (-2) + 14$
$= 12 - 26 + 14$
$= 26 - 26$
$= 0$
$= R.H.S.$
Hence, x = -2 is a solution of the given equation.
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