Question
Show that $x = -3$ is a solution of $x^2 + 6x + 9 = 0.$
✓
Answer
The given equation is $x^2 + 6x + 9 = 0$
If x = -3 is its solution then it will satisfy it.
$L.H.S. = (-3)^2 + 6(-3) + 9$
$= 9 - 18 + 9$
$= 18 - 18$
$= 0$
$= R.H.S.$
Hence $x = -3$ is its one root.
If x = -3 is its solution then it will satisfy it.
$L.H.S. = (-3)^2 + 6(-3) + 9$
$= 9 - 18 + 9$
$= 18 - 18$
$= 0$
$= R.H.S.$
Hence $x = -3$ is its one root.
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