Question
Show the following quadratic equation by factorization method:
$13x^2 - 7x + 1 = 0$

Answer

$13x^2 - 7x + 1 = 0$
We will apply discriminant rule,
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac$
$= 7^2 - 4.13.1$
$= 49 - 52$
$= -3$
From (A)
$\text{x}=\frac{-7\pm\sqrt{-3}}{2.13}$
$=\frac{-7\pm2\sqrt{3}\text{ i}}{26}$
$\therefore\text{x}=\frac{-7}{26}\pm\frac{\sqrt{3}}{26}\ \text{i}$

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