Question
Show the following quadratic equation by factorization method: $17x^2 - 28x + 12 = 0$

Answer

$17x^2 + 28x + 12 = 0$ We will apply discriminant rule, $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac = (-28)^2 - 4.17.12 = 784 - 816 = -32$ From (A) $\text{x}=\frac{-28\pm\sqrt{-32}}{2.17}$ $=\frac{-28\pm4\sqrt{2}\text{i}}{34}$
$\therefore\text{x}=\frac{-14\pm2\sqrt{2}\text{i}}{17}$

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