Show the following quadratic equation by factorization method: 21… - Vidyadip

Question

Show the following quadratic equation by factorization method:
$21x^2 - 28x + 10 = 0$

✓

Answer

$21x^2 - 28x + 10 = 0$
We will apply discriminant rule,
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac$
$= (-28)^2 - 4.21.10$
$= 784 - 840$
$= -56$
From (A)
$\text{x}=\frac{-28\pm\sqrt{-56}}{2.21}$
$=\frac{-28\pm2\sqrt{14}\text{ i}}{42}$
$\therefore\text{x}=\frac{2}{3}\pm\frac{\sqrt{14}}{21}\ \text{i}$

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