Show the following quadratic equation by factorization method: 3x… - Vidyadip

Question

Show the following quadratic equation by factorization method: $3\text{x}-4\text{x}+\frac{20}{3}=0$

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Answer

$3\text{x}-4\text{x}+\frac{20}{3}=0$ We will apply discriminant rule, $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$ Where $D = b^2 - 4ac =(-4)^2-4(3)\Big(\frac{20}{3}\Big)$ = 16 - 80 = -64 From (A) $\text{x}=\frac{-(-4)\pm\sqrt{-64}}{2(3)}$ $=\frac{4\pm\text{i}{8}}{6}$ $=\frac{2}{3}\pm\frac{4\text{i}}{3}$ Thus, $\therefore\text{x}=\frac{2}{3}\pm\frac{4\text{i}}{3}$

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