Show the following quadratic equation by factorization method: 3x… - Vidyadip

Question

Show the following quadratic equation by factorization method:
$3\text{x}-4\text{x}+\frac{20}{3}=0$

✓

Answer

$3\text{x}-4\text{x}+\frac{20}{3}=0$
We will apply discriminant rule,
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac$
$=(-4)^2-4(3)\Big(\frac{20}{3}\Big)$
$= 16 - 80$
$= -64$
From $(A)$
$\text{x}=\frac{-(-4)\pm\sqrt{-64}}{2(3)}$
$=\frac{4\pm\text{i}{8}}{6}$
$=\frac{2}{3}\pm\frac{4\text{i}}{3}$
Thus,
$\therefore\text{x}=\frac{2}{3}\pm\frac{4\text{i}}{3}$

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