Show the following quadratic equation by factorization method: 3x… - Vidyadip

Question

Show the following quadratic equation by factorization method:
$3\text{x}-4\text{x}+\frac{20}{3}=0$

✓

Answer

$3\text{x}-4\text{x}+\frac{20}{3}=0$
We will apply discriminant rule,
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where D = b² - 4ac
$=(-4)^2-4(3)\Big(\frac{20}{3}\Big)$
= 16 - 80
= -64
From (A)
$\text{x}=\frac{-(-4)\pm\sqrt{-64}}{2(3)}$
$=\frac{4\pm\text{i}{8}}{6}$
$=\frac{2}{3}\pm\frac{4\text{i}}{3}$
Thus,
$\therefore\text{x}=\frac{2}{3}\pm\frac{4\text{i}}{3}$

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