Question
Show the following quadratic equation by factorization method: $4 x^2+1=0$

Answer

$4 x^2+1=0 \Rightarrow(2 x)^2-i^2=0\left[\because i^2=-1\right] \Rightarrow(2 x+i)(2 x-i)=0 \Rightarrow$ Either $2 x+i=0$ or $2 x-i=0 \Rightarrow x=\frac{-i}{2}$ or $x=\frac{i}{2}$ $\therefore \mathrm{x}=\frac{-\mathrm{i}}{2}, \frac{\mathrm{i}}{2}$

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