Question
Show the following quadratic equation by factorization method:
$4x^2 + 1 = 0$

Answer

$4x^2 + 1 = 0$
$\Rightarrow (2x)^2 - i^2 = 0$ [$\because$ $i^2 = -1]$
$\Rightarrow (2x + i) (2x - i) = 0$
$\Rightarrow $ Either $2x + i = $0 or $2x - i = 0$
$\Rightarrow\text{x}=\frac{-\text{i}}{2}\ \text{or }\text{x}=\frac{\text{i}}{2}$
$\therefore\text{x}=\frac{-\text{i}}{2},\frac{\text{i}}{2}$

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