Question
Show the following quadratic equation by factorization method: $6 x^2-17 x -12=0$

Answer

$6 x^2-17 i x-12=0 \Rightarrow 6 x^2-17 i x+12 i^2=0 \Rightarrow 6 x^2-9 i x-8 i x+12 i^2=0 \Rightarrow 3 x(2 x-3 i)-4 i(2 x-3 i)=0 \Rightarrow(3 x-4 i)(2 x-3 i)$
$=0 \Rightarrow x=\frac{4}{3} i \text { or } \frac{3}{2} i$

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