Question
Show the following quadratic equation by factorization method: $8x^2 - 9x + 3 = 0$

Answer

$8x^2 - 9x + 3 = 0$ We will apply discriminant rule, $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac = (-9)^2 - 4.8.3 = 81 - 96 = -15$ From (A) $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}$
$=\frac{-(-9)\pm\sqrt{-15}}{2.8}$ $=\frac{-9\pm\sqrt{15}\text{ i}}{16}$ $\therefore\text{x}=\frac{9\pm\sqrt{15}\text{ i}}{16}$

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