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Quadratic Equations — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsQuadratic Equations3 Marks
Question
Show the following quadratic equation by factorization method:
$8x^2 - 9x + 3 = 0$
✓

Answer

$8x^2 - 9x + 3 = 0$
We will apply discriminant rule,
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac$
$= (-9)^2 - 4.8.3$
$= 81 - 96$
$= -15$
From $(A)$
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}$
$=\frac{-(-9)\pm\sqrt{-15}}{2.8}$
$=\frac{-9\pm\sqrt{15}\text{ i}}{16}$
$\therefore\text{x}=\frac{9\pm\sqrt{15}\text{ i}}{16}$

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