Question
Show the following quadratic equation by factorization method: $9\text{x}^2+4=0$

Answer

$9 x^2+4=0 \Rightarrow(3 x)^2-\left(2 i^2\right)=0\left[\because i^2=-1\right] \Rightarrow(3 x+2 i)(3 x-2 i)=0 \Rightarrow\text{x}=\frac{-2}{3}\text{i}\ \text{or}\text{ x}=\frac{2}{3}\text{i}$ $\therefore\text{x}=\frac{-2}{3}\text{ i},\frac{2}{3}\text{ i}$

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