Question
Show the following quadratic equation by factorization method:
$9\text{x}^2+4=0$

Answer

$9x^2 + 4 = 0$
$\Rightarrow (3x)^2 - (2i^2) = 0 [\because i^2 = -1]$
$\Rightarrow (3x + 2i) (3x - 2i) = 0$
$\Rightarrow\text{x}=\frac{-2}{3}\text{i}\ \text{or}\text{ x}=\frac{2}{3}\text{i}$
$\therefore\text{x}=\frac{-2}{3}\text{ i},\frac{2}{3}\text{ i}$

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