Question
Show the following quadratic equation by factorization method:
$\text{x}^2-(2\sqrt{3}+3\text{i}))\text{x}+6\sqrt{3}\text{ i}=0$
$\text{x}^2-(2\sqrt{3}+3\text{i}))\text{x}+6\sqrt{3}\text{ i}=0$
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$\left|\begin{array}{ccc}1 & 4 & 20 \\ 1 & -2 & -5 \\ 1 & 2 x & 5 x^2\end{array}\right|=0$
$f: R \rightarrow R$ given by $f(x)=x^2$