Question
Show the following quadratic equation by factorization method: $\text{x}^2+2\text{x}+5=0$

Answer

$x^2+2 x+5=0$ Now, completing the squares, we get $(x+1)^2+4=0 \Rightarrow(x+1)^2-2 i^2=0 \Rightarrow(x+1+2 i)(x+1-2 i)=$ $0 \Rightarrow(x+1+2 i)=0$ or $(x+1-2 i)=0 \therefore x=-1=2 i,-1+2 i$

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