Question
Show the following quadratic equation by factorization method:
$\text{x}^2+2\text{x}+5=0$

Answer

$x^2 + 2x + 5 = 0$
Now, completing the squares, we get
$(x + 1)^2 + 4 = 0$
$\Rightarrow (x + 1)^2 - 2i^2 = 0$
$\Rightarrow (x + 1 + 2i) (x + 1 - 2i) = 0$
$\Rightarrow (x + 1 + 2i) = 0 or (x + 1 - 2i) = 0$
$\therefore x = -1 = 2i, -1 + 2i$

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