Question
Show the following quadratic equation by factorization method: $x^2 + 1 = 0$

Answer

$x^2+1=0 \Rightarrow x^2+i^2=0\left[\because i^2=-1\right] \Rightarrow(x+i)(x-i)=0\left[a^2-b^2=(a+b)(a-b)\right] \Rightarrow x=i,-i$

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