Question
Show the following quadratic equation by factorization method: $x^2 + 4x + 7 = 0$

Answer

$x^2+4 x+7=0$ We will apply discriminant rule, $x=\frac{-b \pm \sqrt{D}}{2 a} \ldots(A)$ Where $D=b^2-4 a c=(-4)^2-4 \cdot 1 \cdot 7=-12$ From
(A) $\text{x}=-\frac{(-4)\pm\sqrt{-12}}{2}$
$=\frac{4\pm2\sqrt{3}\text{i}}{2}$
$=2\pm\sqrt{3}\text{i}$ $\therefore\text{x}=2+\sqrt{3}\text{i},2-\sqrt{3}\text{i}$

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