Question
Show the following quadratic equation by factorization method: $x^2 + x + 1 = 0$

Answer

$x^2 + x + 1 = 0$ We will apply discriminant rule, $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$ Where $D = b^2 - 4ac = (-1)^2 - 4.1.1 = 1 - 4 = -3$ From (A) $\text{x}=\frac{-1\pm\sqrt{-3}}{2}$
$=\frac{-1\pm\sqrt{3\text{i}}}{2}$ $\therefore\text{x}=\frac{-1}{2}+\frac{\sqrt{3}}{2}\ \text{i},\frac{-1}{2}-\frac{\sqrt{3}}{2}\ \text{i}$

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