Question
Show the following quadratic equation by factorization method:
$x^2 - x + 1 = 0$

Answer

$x^2 - x + 1 = 0$
We will apply discriminant rule,
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac$
$= (-1)^2 - 4.1.1$
$= 1 - 4$
$= -3$
From (A)
$\therefore\text{x}=\frac{-(-1)\pm\sqrt{-3}}{2}$
$=\frac{1\pm\sqrt{3\text{i}}}{2}$
$\therefore\text{x}=\frac{1}{2}+\frac{\sqrt{3}}{2}\ \text{i},\frac{1}{2}-\frac{\sqrt{3}}{2}\ \text{i}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free