Question
Show the following quadratic equation by factorization method: $-x^2 + x - 2 = 0$

Answer

$-x^2 + x - 2 = 0$ We will apply discriminant rule, $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$ Where $D = b^2 - 4ac = 1^2 - 4.(-1). (-2) = 1 - 8 = -7$ From (A) $\text{x}=\frac{-1\pm\sqrt{-7}}{2.\sqrt{-1}}$
$=\frac{-1\pm\sqrt{-7}\text{ i}}{-2}$ Thus, $\therefore\text{x}=\frac{-1\pm\sqrt{7}\text{ i}}{-2}$

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