Question
Show the following quadratic equation: $i x^2-4 x-4 i=0$

Answer

$i x^2-4 x-4 i=0 \Rightarrow i x^2+4 i^2 x+4 i^3=0 \Rightarrow x^2+4 i x+4 i^2=0 \Rightarrow x^2+2 i x+2 i x+4 i^2=0 \Rightarrow x(x+2 i)+2 i(x+2 i)=0 \Rightarrow(x$
$+2 i)(x+2 i) \therefore x=-2 i,-2 i$

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