Question
Show the following quadratic equation:
ix2 - 4x - 4i = 0

Answer

ix2 - 4x - 4i = 0
⇒ ix2 + 4i2x + 4i3 = 0
⇒ x2 + 4ix + 4i2 = 0
⇒ x2 + 2ix + 2ix + 4i2 = 0
⇒ x (x + 2i) + 2i (x + 2i) = 0
⇒ (x + 2i) (x + 2i)
$\therefore\text{x}=-2\text{i},-2\text{i}$

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