Question
Show the following quadratic equation: $x^2+4 i x-4=0$

Answer

$x^2+4 i x-4=0 \Rightarrow x^2+4 i x+4 i^2=0 \Rightarrow x^2+2 i x+2 i x+4 i^2=0 \Rightarrow x(x+2 i)+2 i(x+2 i)=0 \Rightarrow(x+2 i)(x+2 i)=0 \Rightarrow x$
$=-2 i,-2 i$

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