Question
Show the following quadratic equation:
$x^2 + 4ix - 4 = 0$

Answer

$x^2 + 4ix - 4 = 0$
$\Rightarrow x^2 + 4ix + 4i^2 = 0$
$\Rightarrow x^2 + 2ix + 2ix + 4i^2 = 0$
$\Rightarrow x (x + 2i) + 2i (x + 2i) = 0$
$\Rightarrow (x + 2i) (x + 2i) = 0$
$\Rightarrow x = -2i, -2i$

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