Question
Show the following quadratic equation:
$x^2 + 4ix - 4 = 0$
$x^2 + 4ix - 4 = 0$
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$\left(x^2-\frac{1}{x}\right)^9$
$\frac{a+b w+c w^2}{c+a w+b w^2}=\omega^2$