Question
Show thet the followiong sequences is an A.P. Also, find the common difference and write 3 more terms in each case. $3,-1,-5,-9...$

Answer

$3,-1,-5,-9...$ $​​\text{a}_1=3,​​\text{a}_2=-1,​​\text{a}_3=-5,​​\text{a}_4=-4$ $​​\text{a}_2-​​\text{a}_1=-1-3=-4$ $​​\text{a}_3-​​\text{a}_2=-5-(-1)=-4$ $​​\text{a}_4-​​\text{a}_3-=9(-5)=-4$ $\therefore$ common difirence is $=-4$ $​​\text{a}_4-​​\text{a}_3=​​\text{a}_3-​​\text{a}_2=​​\text{a}$ $\therefore$ The given sequerence is a A.P $\therefore​​\text{a}_5=3+(5-1)(-4)=-13$ $​​\text{a}_6=3+(6-1)(-4)=-17$ $​​\text{a}_7=3+(7-1)(-4)=-21$

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