Question
Show thet the followiong sequences is an A.P. Also, find the common difference and write 3 more terms in each case.
$-1,\frac{1}{4},\frac{3}{2},\frac{11}{4},...$

Answer

$-1,\frac{1}{4},\frac{3}{2},\frac{11}{4},...$
$​​\text{a}_1=-1,​​\text{a}_2=\frac{1}{4},​​\text{a}_3=\frac{3}{2},​​\text{a}_4=\frac{11}{4}$
$​​\text{a}_4-​​\text{a}_3=​​\text{a}_3-​​\text{a}_2=​​\text{a}_2-​​\text{a}_1=\frac{5}{4}$
$\therefore$ common differnce is $​​\text{d}=\frac{5}{4}$
$\therefore$ The given sequence is A.P
$\text{a}_5=-1+(5-1)\frac{5}{4}=4$
$\text{a}_6=-1+(6-1)\frac{5}{4}=\frac{21}{4}$
$\text{a}_5=-1+(5-1)\frac{5}{4}=\text{a}_{4}$
$=-1+(7-1)\frac{5}{4}=\frac{26}{4}=\frac{13}{2}$

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