MCQ
$SiCl_4$ on hydrolysis gives
- Asilica
- ✓silicic acid
- Csilicone
- Dsilicate
The reaction is as follows:
$\mathrm{SiCl}_{4}+4 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Si}(\mathrm{OH})_{4}+4 \mathrm{HCl}$
Hence, silicic acid is formed when $\mathrm{SiCl}_{4}$ undergoes hydrolysis.
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(Given that : $SrCO_{3(s)} \rightleftharpoons SrO_{(s)}+ CO_{2(g)} \,, K_p=1.6\,atm$)
$(\log \,4 = 0.60,\, \log \,5 = 0.69)$
$\begin{array}{*{20}{c}}
{BrC{H_2} - CH - CO - C{H_2} - C{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{CON{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
is :