Question
Silver atom has completely filled d orbitals $(4d^{10})$ in its ground state. How can you say that it is a transition element?
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Answer
The outer electronic configuration of Ag $(Z = 47)$ is $4d^{10}5s^1.$
It shows $+1$ and $+2O.S$. $($in $AgO$ and $AgF_2)$. And in $+2O.S. ,$
the electronic configuration is $d^9$
i.e., $d -$ subshell is incompletely filled. Hence, it is a transition element.
It shows $+1$ and $+2O.S$. $($in $AgO$ and $AgF_2)$. And in $+2O.S. ,$
the electronic configuration is $d^9$
i.e., $d -$ subshell is incompletely filled. Hence, it is a transition element.
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