Question
Silver crystallizes in face-centered cubic unit cell. Each side of this unit cell has a length of 400 pm. Calculate the radius of the silver atom. (Assume the atoms just touch each other on the diagonal across the face of the unit cell. That is each face atomis touching the four comer atoms.)

Answer

For fcc unit cell
$\text{r}=\frac{\text{a}}{2\sqrt{2}}$
Given a = 400 pm
$\therefore\text{r}=400/2\sqrt{2}\text{pm}$
$\text{r} =141.4 \text{pm}.$

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