Question
Simplify:$15\frac{3}{7}\div1\frac{23}{49}$
✓
Answer
$15\frac{3}{7}\div1\frac{23}{49}=\frac{108}{7}\div\frac{72}{49}=\frac{108}{7}\times\frac{49}{72}$$=\frac{3\times{7}}{1\times2}=\frac{21}{2}=10\frac{1}{2}$
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