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Substitution (Including Use of Brackets as Grouping Symbols) — MATHS STD 6 — Question

ICSE BoardEnglish MediumSTD 6MATHSSubstitution (Including Use of Brackets as Grouping Symbols)3 Marks
Question
Simplify:
$2 (3x^2 – 4x – 8) – (3 – 5x – 2x^2)$
✓

Answer

$2 (3x^2 – 4x – 8) – (3 – 5x – 2x^2)$
$= (6x^2 – 8x – 16) – (3 – 5x – 2x^2)$
$= 6x^2 – 8x – 16 – 3 + 5x + 2x^2$
$= 6x^2 + 2x^2 – 8x + 5x – 16 – 3$
$= 8x^2 – 3x – 19$

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