Question
Simplify:$2+\frac{11}{15}-\frac{5}{9}$
✓
Answer
We have:$2+\frac{11}{15}-\frac{5}{9}$
$\begin{array}{c|c}3&1,15,9\\\hline3&1,5,3\ \\\hline5&1,5,1\ \\\hline&1,1,1\ \end{array}$
$L.C.M.$ of $15$ and $9 = (3 \times 3 \times 5) = 45$
$=\frac{(90+33-25)}{45}$
$\Big(\frac{45}{1}=45,45\times2=90\Big)$
$\Big(\frac{45}{15}=3,3\times11=33\Big)$ and
$\Big(\frac{45}{9}=5,5\times5=25\Big)$
$=\frac{(98+8)}{45}$
$=\frac{98}{45}$
$=2\frac{8}{45}$
$\begin{array}{c|c}3&1,15,9\\\hline3&1,5,3\ \\\hline5&1,5,1\ \\\hline&1,1,1\ \end{array}$
$L.C.M.$ of $15$ and $9 = (3 \times 3 \times 5) = 45$
$=\frac{(90+33-25)}{45}$
$\Big(\frac{45}{1}=45,45\times2=90\Big)$
$\Big(\frac{45}{15}=3,3\times11=33\Big)$ and
$\Big(\frac{45}{9}=5,5\times5=25\Big)$
$=\frac{(98+8)}{45}$
$=\frac{98}{45}$
$=2\frac{8}{45}$
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