Question
Simplify:$(2^{2}+3^2-4^2)\div\Big(\frac{3}{2}\Big)^2$

Answer

$(2^{2}+3^2-4^2)\div\Big(\frac{3}{2}\Big)^2$
$=(4\div9-16)\div\frac{9}{4}=-3\times\frac{4}{9}$
$=\frac{-1\times4}{3}=\frac{-4}{3}$

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