Question
Simplify:
$2 p^3-3 p^2+4 p-5-6 p^3+2 p^2-8 p-2+6 p+8$
$2 p^3-3 p^2+4 p-5-6 p^3+2 p^2-8 p-2+6 p+8$
✓
Answer
$2 p^3-3 p^2+4 p-5-6 p^3+2 p^2-8 p-2+6 p+8$
$=2 p^3-6 p^3-3 p^2+2 p^2+4 p+6 p-5-2+8$
$=-6 p^3-p^2+10 p+1$
$=2 p^3-6 p^3-3 p^2+2 p^2+4 p+6 p-5-2+8$
$=-6 p^3-p^2+10 p+1$
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