Question
Simplify:
$-2(x^2 - y^2 + xy) - 3(x^2 + y^2 - xy)$
$-2(x^2 - y^2 + xy) - 3(x^2 + y^2 - xy)$
✓
Answer
We have:
$-2(x^2 - y^2+ xy) - 3(x^2 + y^2 - xy)$
$= -2x^2 + 2y^2 - 2xy - 3x^2 - 3y^2 + 3xy$
$= -2x^2 - 3x^2 + 2y^2 - 3y^2 - 2xy + 3xy$
$= (-2 - 3)x^2 + (2 - 3) y^2 + (- 2 + 3)xy$
$= -5x^2 - y^2 + xy$
$-2(x^2 - y^2+ xy) - 3(x^2 + y^2 - xy)$
$= -2x^2 + 2y^2 - 2xy - 3x^2 - 3y^2 + 3xy$
$= -2x^2 - 3x^2 + 2y^2 - 3y^2 - 2xy + 3xy$
$= (-2 - 3)x^2 + (2 - 3) y^2 + (- 2 + 3)xy$
$= -5x^2 - y^2 + xy$
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