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Exponents and Powers — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSExponents and Powers1 Mark
MCQ
Simplify $(-3)^{-5} \times (7)^{-5} \times (4)^{-5}$ and write the answer in exponent form:
  • A
    $(- 84)^5$
  • B
    $(84)^5$
  • C
    $\frac{1}{(84)^5}$
  • ✓
    $\frac{1}{(-84)^5}$
✓

Answer

Correct option: D.
$\frac{1}{(-84)^5}$
D.  $\frac{1}{(-84)^5}$
Solution:
$(-3)^-5 × (7)^-5 × (4)^-5 = [(-3) × 7 × 4]^-5$
$= (-84)^-5$
$=\frac{1}{(-84)^5}$

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