Question
Simplify:
$3 - [x - {2y - (5x + y - 3) + 2x^2} - (x^2 - 3y)]$
$3 - [x - {2y - (5x + y - 3) + 2x^2} - (x^2 - 3y)]$
✓
Answer
Removing the innermost grouping symbol ( ) first, then { } and then [ ], we have:
$3 - [x - {2y - (5x + y - 3) + 2x^2} - (x^2 - 3y)]$
$= 3 - [x - {2y - 5x - y + 3 + 2x^2} - x^2 + 3y]$
$= 3 - [x - {y - 5x + 3 + 2x^2} - x^2 + 3y]$
$= 3 - [x - y + 5x - 3 - 2x^2 - x^2 + 3y]$
$= 3 - [6x + 2y - 3 - 3x^2]$
$= 3 - 6x - 2y + 3 + 3x^2$
$= 6 - 6x - 2y + 3x^2$
$3 - [x - {2y - (5x + y - 3) + 2x^2} - (x^2 - 3y)]$
$= 3 - [x - {2y - 5x - y + 3 + 2x^2} - x^2 + 3y]$
$= 3 - [x - {y - 5x + 3 + 2x^2} - x^2 + 3y]$
$= 3 - [x - y + 5x - 3 - 2x^2 - x^2 + 3y]$
$= 3 - [6x + 2y - 3 - 3x^2]$
$= 3 - 6x - 2y + 3 + 3x^2$
$= 6 - 6x - 2y + 3x^2$
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