Question
Simplify:$(3^2-2^2)\times\Big(\frac{2}{3}\Big)^{-3}$
✓
Answer
$(3^2-2^2)\times\Big(\frac{2}{3}\Big)^{-3}$
$=(9-4)\times\Big(\frac{3}{2}\Big)^3$
$=5\times\frac{27}{8}=\frac{135}{8}$
$=(9-4)\times\Big(\frac{3}{2}\Big)^3$
$=5\times\frac{27}{8}=\frac{135}{8}$
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