Question
Simplify:$(3^2+2^2)\times\Big(\frac{1}{2}\Big)^3$

Answer

$(3^2+2^2)\times\Big(\frac{1}{2}\Big)^3$
$=(9\div4)\times\frac{1}{8}=13\times\frac{1}{8}$
$=\frac{13}{8}$

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