Question
Simplify $: 35xy^5 \div 7x^2y^4$
✓
Answer
$35 x y^5 \div 7 x^2 y^4$
$=\frac{5 \times 7 \times y^{5-4}}{7 \times x^{2-1}}$
$=\frac{5 y}{x}$
$=\frac{5 \times 7 \times y^{5-4}}{7 \times x^{2-1}}$
$=\frac{5 y}{x}$
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