Question
Simplify: $(4^{-1}\times3^{-1})^2$
✓
Answer
$(4^{-1}\times3^{-1})^2=\Big(\frac{1}{4}\times\frac{1}{3}\Big)^2=\Big(\frac{1}{12}\Big)^2$
$=\frac{1}{12}\times\frac{1}{12}=\frac{1}{144}$
$=\frac{1}{12}\times\frac{1}{12}=\frac{1}{144}$
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