Question
Simplify : $4 \sqrt{12}-\sqrt{75}-7 \sqrt{48}$
✓
Answer
$\begin{aligned} & 4 \sqrt{12}-\sqrt{75}-7 \sqrt{48} \\ = & 4 \sqrt{4 \times 3}-\sqrt{25 \times 3}-7 \sqrt{16 \times 3} \\ = & 4 \times 2 \sqrt{3}-5 \sqrt{3}-7 \times 4 \sqrt{3} \\ = & 8 \sqrt{3}-5 \sqrt{3}-28 \sqrt{3} \\ = & (8-5-28) \sqrt{3} \\ = & (-25) \sqrt{3} \\ \therefore \quad & 4 \sqrt{12}-\sqrt{75}-7 \sqrt{48}=-25 \sqrt{3}\end{aligned}$
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