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Exponents and Powers — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSExponents and Powers1 Mark
Question
Simplify: $\frac{49\times\text{z}^{-3}}{7^{-3}\times10\times\text{z}^{-5}}(\text{z}\neq0)$
✓

Answer

$\frac{49\times\text{z}^{-3}}{7^{-3}\times10\times\text{z}^{-5}}$
$=\frac{(7)^2\times\text{z}^{-3}}{7^{-3}\times10\times\text{z}^{-5}}$
 $=\frac{(7)^{2+3}\times\text{z}^{-3+5}}{10}$ $\left[\because a^m \div a^n=(a)^{m-n}\right]$
$=\frac{(7)^5\text{z}^2}{10}=\frac{7^5}{10}\text{z}^2$

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