Question
Simplify:$5\frac{3}{4}-4\frac{5}{12}+3\frac{1}{6}$
✓
Answer
We have:$5\frac{3}{4}-4\frac{5}{12}+3\frac{1}{6}$
$\frac{23}{4}-\frac{53}{12}+\frac{19}{6}$
$\begin{array}{c|c}2&4,12,6\\\hline2&2,6,3\\\hline3&1,2,3\\\hline2&1,2,1\\\hline&1,1,1\end{array}$
$L.C.M$. of $4, 12$ and $6 = (2 \times 2 \times 3) = 12$
$=\frac{(69-53+38)}{12}$
$\Big(\frac{12}{4}=3,3\times23=69\Big)$
$\Big(\frac{12}{12}=1,1\times53=53\Big)$ and
$\Big(\frac{12}{6}=2,2\times19=38\Big)$
$=\frac{(107-53)}{12}$
$=\frac{54}{12}$
$=\frac{9}{2}$
$=4\frac{1}{2}$
$\frac{23}{4}-\frac{53}{12}+\frac{19}{6}$
$\begin{array}{c|c}2&4,12,6\\\hline2&2,6,3\\\hline3&1,2,3\\\hline2&1,2,1\\\hline&1,1,1\end{array}$
$L.C.M$. of $4, 12$ and $6 = (2 \times 2 \times 3) = 12$
$=\frac{(69-53+38)}{12}$
$\Big(\frac{12}{4}=3,3\times23=69\Big)$
$\Big(\frac{12}{12}=1,1\times53=53\Big)$ and
$\Big(\frac{12}{6}=2,2\times19=38\Big)$
$=\frac{(107-53)}{12}$
$=\frac{54}{12}$
$=\frac{9}{2}$
$=4\frac{1}{2}$
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