Question
Simplify:$5\frac{3}{4}-4\frac{5}{12}+3\frac{1}{6}$

Answer

We have:$5\frac{3}{4}-4\frac{5}{12}+3\frac{1}{6}$
$\frac{23}{4}-\frac{53}{12}+\frac{19}{6}$
$\begin{array}{c|c}2&4,12,6\\\hline2&2,6,3\\\hline3&1,2,3\\\hline2&1,2,1\\\hline&1,1,1\end{array}$
L.C.M. of 4, 12 and 6 = (2 × 2 × 3) = 12 $=\frac{(69-53+38)}{12}$ $\Big(\frac{12}{4}=3,3\times23=69\Big)$ $\Big(\frac{12}{12}=1,1\times53=53\Big)$ and $\Big(\frac{12}{6}=2,2\times19=38\Big)$$=\frac{(107-53)}{12}$
$=\frac{54}{12}$
$=\frac{9}{2}$
$=4\frac{1}{2}$

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